Via Current and Barrel Resistance Calculator

Works out the plated barrel cross-section from drill diameter and plating thickness, then uses the same IPC-2221 fit to estimate how much current one via carries, together with barrel resistance, drop and dissipation. Calculated in the browser; nothing is uploaded.

Your inputs stay in this browserNo sign-in · free · no quotaDefault inputs already computed server-side
mm
µm
°C
mm
pcs

Result

Current per via1.90 A
Arithmetic sum for that count (not derated)1.90 A
Required cross-section area39.6 mil²
Plating thickness in mil0.984 mil
Barrel resistance per via1.078 mΩ
Drop per via at that current2.051 mV
Dissipation per via3.90 mW

Worked examples

Every row is produced by our Python reference implementation using the same constants and thresholds the page recalculates with; decimals go only as far as you can hand-check.

CaseInputsCurrent per via AArithmetic sum for that count (not derated) ARequired cross-section area mil²Plating thickness in mil milBarrel resistance per via mΩDrop per via at that current mVDissipation per via mW
0.3 mm drill with 25 µm plating, outer layer, 10 °C rise0.3 mm · 25 µm · 10 °C · outer · 1.6 mm · 1 pcs1.901.9039.60.9841.0782.0513.90
The same via with 18 µm plating (thin-copper process)0.3 mm · 18 µm · 10 °C · outer · 1.6 mm · 1 pcs1.481.4827.90.7091.5302.2583.33
20 × 0.3 mm vias in parallel: the total is only one via × 20, with no derating0.3 mm · 25 µm · 10 °C · outer · 1.6 mm · 20 pcs1.9038.0539.60.9841.0782.0513.90

Where the number comes from

A = π · (d + t) · t I = k · ΔT^0.44 · A^0.725 R = ρ · L / A
  • d: drill diameter before plating (mil)
  • t: barrel plating thickness (mil); 1 oz = 1.378 mil, 1 µm = 0.03937 mil
  • k: 0.048 (outer) / 0.024 (internal), ΔT being the allowed rise
  • ρ: annealed copper resistivity at 20 °C = 0.0172 Ω·mm²/m, with L taken as the board thickness

The fit reproduces the published IPC-2221 current capacity chart; it is not the standard text. All constants are listed below, please check them.

Constants: k=0.048 (outer layer) / 0.024 (internal layer) · b=0.44 · c=0.725 · 1 oz=1.378 mil=35 µm · 1 mil=0.0254 mm=25.4 µm · rho(Cu, 20 °C)=0.0172 ohm·mm²/m

What this result cannot be used to decide

This is via geometry × a temperature-rise model. It does not cover the plating uniformity declared by the fab or aspect-ratio capability, thermal-cycle and reflow reliability or the solder fill inside the hole, and it cannot know how current actually splits between several vias. Production sign-off needs a fab process confirmation and a measured temperature rise.

Frequently asked questions

How much current can one via really carry?

The dominant term is the plated barrel cross-section, A = π·(d+t)·t — so hole size and plating thickness, not the drill diameter alone. A 0.3 mm via with 25 µm plating, outer layer, 10 °C rise comes out around 1.9 A.

Can I multiply the current by paralleling vias?

Arithmetically yes, and the page reports one via × count as that sum — but do not treat it as a guaranteed value. How current splits depends on the pads and copper paths, and closely spaced vias heat each other. We deliberately do not print a "×0.7 derating" number, because that only holds once you have your own thermal boundary conditions.

What plating thickness should I enter?

Typical fab electroplated barrels land around 18-25 µm, so 25 µm is the common assumption; once you have the fab cross-section report, use the measured value. Below 15 µm the page flags that you have left the normal band.

Is the barrel resistance useful?

Negligible for small-signal paths (milliohms), but worth counting above about 1 A, or when doing current sensing and voltage-drop budgets. It is computed as R = ρL/A with L equal to the board thickness, which is a conservative upper bound since real plating is more resistive than bulk copper.

Why is the internal-layer figure lower?

The same fit with k = 0.024 for internal layers: heat stays trapped in the dielectric. In real boards, whether the via lands on a large pad or thick copper often changes the answer more than that coefficient does.

Related on this site

Data and formulas last checked:2026-11-02

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